The balanced equation for the combustion of ethanol (ethyl alcohol) is: C2H5OH(l) + 3O2(g) ---> 2CO2(g) + 3H2O(g) How many mol of O2 will react with 7 mol of ethanol?

21 mol of O₂ will react

Explanation:

Based on the combustion of ethanol:

C₂H₅OH(l) + 3O₂(g) → 2CO₂(g) + 3H₂O(g)

1 mole of ethanol, C₂H₅OH reacts with 3 moles of O₂

With this ratio of 1 mol C₂H₅OH / 3 moles O₂ we can solve the moles of O₂ that react with 7mol of ethanol:

7 mol C₂H₅OH * (3mol O₂ / 1 mol C₂H₅OH) =

- lead + phosphoric acid = hydrogen + lead(ii) phosphate