A container of carbon dioxide has a volume of 220.0 cm3 at a temperature of 26.0 °C. If the pressure remains constant, what is the volume at 47.0 °C?

235.45 cm³

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 220 cm³

Initial temperature (T₁) = 26 °C

Final temperature (T₂) = 47 °C

Pressure = constant

Final volume (V₂) =?

Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Initial temperature (T₁) = 26 °C

Initial temperature (T₁) = 26 °C + 273

Initial temperature (T₁) = 299 K

Final temperature (T₂) = 47 °C

Final temperature (T₂) = 47 °C + 273

Final temperature (T₂) = 320 K

Finally, we shall determine the volume (i.e V₂) at 47 °C as follow:

Initial volume (V₁) = 220 cm³

Initial temperature (T₁) = 299 K

Final temperature (T₂) = 320 K

Final volume (V₂) =?

V₁ / T₁ = V₂ / T₂

220 / 299 = V₂ / 320

Cross multiply

299 × V₂ = 220 × 320

299 × V₂ = 70400

Divide both side by 299

V₂ = 70400 / 299

V₂ = 235.45 cm³

Thus, the volume at 47 °C is 235.45 cm³

the answer is:  

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