How many moles of isooctane must be burned to produce 100 kj of heat under standard state conditions? show all of your work.

We would need 0.037 mol. We know that because of a formula we can use and some data from the problem. The formula would be:

n= Number of heat in kj x 2 moles
   
            5460 kJ
The number of Kj of heat is provided(100 kJ). The standard enthalpy of combustion is -5460.0 kj. so we multiply 100 kj and 2 moles and then we divide on 5460 kj and the answer is 0.037 moles. 

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