0.38 L of HNO3 is titrated to equivalence using 0.14 L of 0.2 MNaOH. What is the concentration of the HNO3HNO3

0.074M is concentration of the HNO₃ solution

Explanation:

The reaction of neutralization of nitric acid, HNO₃ with NaOH is:

HNO₃ + NaOH → H₂O + NaNO₃

Where 1 mole of nitric acid reacts per mole of NaOH

Based on the chemical reaction, the moles of NaOH at equivalence point are equal to moles of HNO₃ presents in the solution. With the moles and the volume we can find molarity as follows:

Moles NaOH = Moles HNO₃:

0.14L * (0.2mol NaOH / L) = 0.028mol NaOH  = 0.028mol HNO₃

Molarity:

0.028mol HNO₃ / 0.38L =

answer: the figure is attached herewith.

step-by-step explanation:   we are given to sketch a unit circle and label the terminal points corresponding to

in the attached figure, we have drawn a unit circle, with centre at o(0,0) and radius 1 unit. we have labelled the points a, b, c, d and e corresponding to the angles below

∠aox = 60°,

∠box = 120°,

∠cox = 180°,

∠dox = 240°,

∠eox = 300°.

and the coordinates are a(0.5,1), b(-0.5,1), c(-1,0), d(-0.5,-1) and e(0.5,-1).

thus, the answer is complete.

i do not get it   at all