How do you balance Sb+I2=SbI3 show work please

 2Sb   +    3I₂    →    2SbI₃

Explanation:

The reaction expression we need to balance is:

         Sb   +    I₂    →    SbI₃

To balance this expression, we need to assign the variables a,b and c to each specie as the coefficient that will balance the expression.

              aSb   +    bI₂    →    cSbI₃

Conserving Sb :  a  = c

                      I :   2b  = 3c

let a  = 1, c  = 1,  b  =  

   Multiply through by 2;

 a  = 2, b  = 3  and c  = 2

         2Sb   +    3I₂    →    2SbI₃

hi,

the answer is d, it has indefinite shape but definite volume.

hope this !