If 63.4 J of heat are added to a sample of aluminum with a mass of 16.33 g, what is
its temperature change? The specific heat of
aluminum is 0.899 J/g °C

dt = 4.32°C

Explanation:

Given the following data;

Mass = 16.33g

Quantity of heat, Q = 63.4J

Specific heat capacity = 0.899 J/g °C

To find the temperature change;

Heat capacity is given by the formula;

Where;

Q represents the heat capacity or quantity of heat. m represents the mass of an object. c represents the specific heat capacity of water. dt represents the change in temperature.

Making dt the subject of formula;

Substituting into the equation, we have;

dt = 4.32°C

Therefore, the change in temperature for this aluminum is equal to 4.32°C.

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