Chemistry, 21.01.2021 04:50, scottkayce

2. BaO + H2SO4 —> BaSO + H2O
A) How much BaSo4 can be formed from 196.0 g of H2SO4?

B) How many moles of H2O, are formed when 345.0 g of Bao are reacted with excess H2SO4?

2.

BaO + H2SO4 —> BaSO + H2O
A) How much BaSo4 can be formed from 196.0 g of H2SO4?
B) How man

Answers: 3

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Answers

answered: bunnyqueen124

A. 466 g of BaSO₄.

B. 2.25 moles of H₂O.

Explanation:

The balanced equation for the reaction is given below:

BaO + H₂SO₄ —> BaSO₄ + H₂O

Next, we shall determine the mass of H₂SO₄ that reacted and the mass of BaSO₄ produced from the balanced equation. This can be obtained as follow:

Molar mass of H₂SO₄ = (2×1) + 32 + (16×4)

= 2 + 32 + 64

= 98 g/mol

Mass of H₂SO₄ from the balanced equation = 1 × 98 = 98 g

Molar mass of BaSO₄ = 137 + 32 + (16×4)

= 137 + 32 + 64

= 233 g/mol

Mass of BaSO₄ from the balanced equation = 1 × 233 = 233 g

SUMMARY:

From the balanced equation above,

98 g of H₂SO₄ reacted to produce 233 g of BaSO₄.

A. Determination of the mass of BaSO₄ produced by the reaction of 196 g of H₂SO₄.

From the balanced equation above,

98 g of H₂SO₄ reacted to produce 233 g of BaSO₄.

Therefore, 196 g of H₂SO₄ will react to produce = (196 × 233) /98 = 466 g of BaSO₄.

Thus, 466 g of BaSO₄ were obtained from the reaction.

B. Determination of the number of mole of H₂O produced by the reaction of 345 g of BaO.

We'll begin by calculating the number of mole in 345 g of BaO. This can be obtained as follow:

Mass of BaO = 345 g

Molar mass of BaO = 137 + 16 = 153 g/mol

Mole of BaO =?

Mole = mass /Molar mass

Mole of BaO = 345 / 153

Mole of BaO = 2.25 moles

Finally, we shall determine the number of mole of H₂O produced from the reaction. This can be obtained as follow:

BaO + H₂SO₄ —> BaSO₄ + H₂O

From the balanced equation above,

1 mole of BaO reacted to produce 1 mole of H₂O.

Therefore, 2.25 moles of BaO will also react to produce 2.25 moles of H₂O.

Thus, 2.25 moles of H₂O were obtained from the reaction.

answered: Guest

For cyclohexane compounds drawn in a chair conformation: -axial bonds are vertical -equatorial bonds are parallel to two bonds within the ring. thus, as i assume the chair conformation is drawn: -the x group is in an axial position, as are the five other vertical bonds. -three axial bonds are on the top face of the ring -the other three axial bonds are on the bottom face the position of the second substituent on each ring carbon is equatorial. gauche groups must be on an adjacent carbon such as carbon 6 and carbon 2, and also gauche groups are rotated by 60 degrees relative to each other. drawing the newman projections for c1–c2 and c1–c6 aids in visualizing the groups that are gauche to the y group on c1. click this link and watch some academic videos that may you more understand the topic

answered: Guest

aquifers are bounded above and below by impermeable rock. the driving force of groundwater movement in confined aquifers is pressure, rather than gravity.

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2. BaO + H2SO4 —> BaSO + H2O
A) How much BaSo4 can be formed from 196.0 g of H2SO4?
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