What is the [H ] of a solution of 0.001 M aqueous sulfuric acid (H2SO4) is H2SO4 ionizes in water according to the balanced chemical equation below? H2SO4 --> 2 H+ + SO42-

 0.002 M

Explanation:

The balanced chemical equation for ionization of in water is:

According to stoichiometry :

1 mole of ionizes to give =2 mole of ions

0.001 mole of ionizes to give = mole of ions

Thus of a solution of 0.001 M aqueous sulfuric acid is 0.002 M

93.2 ml + 3920 ml = 4013 ml total  

(93.2 ml) * (2.03 m) / (4013 ml) = 0.0471 m

the volume in in l of the diluted solution would be 0.0471 m.

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