What is the volume of a gas at 253K if the gas occupies 50.0 mL at a temp of 273K? Provided pressure is held constant.

V₂ = 46.34 mL

Explanation:

Given data:

Initial temperature = 273 K

Initial volume = 50.0 mL

Final temperature = 253 K

Final volume = ?

Solution:

The given problem will be solve through the Charles Law.

Charles Law

"The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure"

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

by putting values in formula,

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 50.0 mL × 253 K / 273 k

V₂ = 12650 mL.K / 273 K

V₂ = 46.34mL

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