A player from team A was awarded two free throws. On the first attempt, he released the ball with a velocity of 6.0m/s at 45* above the horizontal from the height of 2.0 m from the floor. (a) Is this a miss? (b) For the second attempt, the player shoots at 45* from the same point. What must be the initial speed of the ball so that it will go through the basket? The basket is 4.21 m from the free throw line and 3.05 m above the floor. heeellppp meee pleassee...T^T

a)

Hmax=v2sin⁡2452g+hH_{max}=\frac{v^2\sin^2{45}}{2g}+hHmax=2gv2sin245+h

Hmax=2+62sin⁡2452(9.81)=2.92 mH_{max}=2+\frac{6^2\sin^2{45}}{2(9.81)}=2.92\ mHmax=2+2(9.81)62sin245=2.92 m

It is less than the height of the basket of 3.05 m. So, this is a miss.

b)

d=R=v2sin⁡(2⋅45)g=v2gd=R=\frac{v^2\sin{(2\cdot45)}}{g}=\frac{v^2}{g}d=R=gv2sin(2⋅45)=gv2

4.21=v29.814.21=\frac{v^2}{9.81}4.21=9.81v2

v=6.43msv=6.43\frac{m}{s}v=6.43sm

explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is and electronic configuration of phosphorous is .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.  

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.

elements make up everything, and they combine to make compounds.

the answer is c