Plz help it's urgent

The number of moles left = 0.0067 moles

Given

0.28 g CO

2 x 10²¹ molecules removed

Required

Number of moles left

Solution

Initial mol of CO(MW=28 g/mol) :

mol = 0.28 : 28

mol = 0.01

The number of molecules in 0.01 mol :

= 0.01 x 6.02 x 10²³

= 6.02 x 10²¹

2 x 10²¹ molecules removed, so molecules left :

= 6.02 x 10²¹ - 2 x 10²¹

= 4.02 x 10²¹

moles of 4.02 x 10²¹ :

= 4.02 x 10²¹ : 6.02 x 10²³

= 0.0067 moles

c. 75.7

i think that is the right

that tool would be a compass