What volume, IN MILLILITERS, of 5.0M HCl solution is required to react with 3.00 g or magnesium metal?

The volume of HCl = 2.10⁴ mL

Given

5.0 M(mol/L) HCl solution

3 g of Mg

Required

Volume of HCl

Solution

Reaction

Mg + 2HCl ⇒ MgCl₂ + H₂

mol of Mg (Ar=24 g/mol) :

mol = mass : Ar

mol = 3 : 24

mol = 0.125

From the equation, mol ratio of Mg : HCl = 1 : 2, so mol HCl :

= 2/1 x mol Mg

= 2 x 0.125

= 0.25

Molarity : mol solute per liters solution

M = m x V

V = M : m

V = 5 mol/L : 0.25

V = 20 L = 2.10⁴ mL

if the concentration of products is decreased, the equilibrium will shift toward the products). add an inert gas (one that is not involved in the reaction) to the constant-volume reaction mixture: this will increase the total pressure of the system, but will have no effect on the equilibrium condition.

explanation:

air quality

poor drinking water

and heavy polution

can lead to poor health