Determine the mass of 840 cm3 of oxygen gas, O2 at rtp

Mass = 0.96 g

Explanation:

Given data:

Volume of oxygen = 840cm³

Temperature = at room = 25°C

Pressure = at room = 1 atm

Mass of oxygen = ?

Solution:

Volume of oxygen = 840 cm³ × 1 L /1000 cm³ = 0.84 L

Temperature  = 25 +273.15k = 298.15 K

Formula:

PV = nRT

n = PV/RT

R = 0.0821 atm.L/mol.K

n = 1 atm × 0.84 L / 0.0821 atm.L/mol.K ×  298.15 K

n = 0.84 atm.L / 24.48 atm.L/mol

n = 0.03 mol

Mass of oxygen:

Mass = number of moles × molar mass

Mass = 0.03 mol × 32 g/mol

Mass = 0.96 g

the increase of protons   hope this

metals are good conductor of electricity. it has free electrons on their surface. according to electron pool theory, each atom present in a metal crystal losses all of its valence electron and as a result a pool of free is form. these pool of electrons are free to move and   conduct electricity easily   while making metal as good conductor.

the correct answer is a. the ability of electrons to flow throughout the metal.

if it's not useful, feel free to report for mistake in answer.