What is the mole fraction of cation in 1M of aluminium sulphate

The mole fraction of cation (Al)=0.4

Given

1 M of Aluminium sulphate

Required

The mole fraction of cation

Solution

Ionization of the Aluminum sulfate solution( assume 1 L solution ) :

mol Al₂(SO₄)₃ = M x V = 1 M x 1 L = 1 mol

Al₂(SO₄)₃⇒2Al³⁺ + 3SO₄²⁻

1 mol          2 mol   3 mol

From this equation, total mol in solution = 2+3 = 5 moles

Mol fraction Al(as a cation) :

= 2/5=0.4

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