A photon has an energy of 2.78 x 1032 J. What is its wavelength?

7.14 × 10^(-58) m

Explanation:

We are given;

Energy; E = 2.78 x 10^(32) J

Formula to find this energy is;

E = hc/λ

Where;

E is energy

h is Planck's constant with a constant value of 6.62 × 10^(-34) J/s

c is speed of light with a constant value of 3 × 10^(8) m/s

λ is wavelength

Making λ the subject, we have;

λ = hc/E

λ = (6.62 × 10^(-34) × 3 × 10^(8))/(2.78 x 10^(32))

λ = 7.14 × 10^(-58) m

a 20-cm-long, cylindrical graphite (pure carbon) rod is inserted into an oxidizing atmosphere at 1145 k and 1.013 x 105 pa pressure. the oxidizing process is limited by the diffu- sion of oxygen counterflow to the carbon monoxide that is formed on the cylindrical surface.