: Mechanical advantage is the ratio of output force to input force. In this part of the task, you'll explore mechanical advantage using a simulation in which you use a ramp (inclined plane) to put a crate into the back of a truck.

Open the inclined plane simulation. Keep all the default presets except for friction; set this to 0. To run the simulation, click on the crate and drag it up the ramp until the force arrow turns green, indicating that you're pulling with enough force to move the crate. Note that your actual mechanical advantage (Actual MA in the Outputs) is 2.24.

Reset the simulation, and return the friction to 0. How can you alter the ramp's length and height to increase its mechanical advantage? Does increasing the mechanical advantage make it harder or easier to push the crate up the ramp?

The highway above switches back and forth as it climbs up the steep hillside. The much gentler slope of the road makes it easier for vehicles to reach the top of the mountain. The highway is an example of an inclined plane.

What Is An Inclined Plane?

An inclined plane is a simple machine that consists of a sloping surface connecting a lower elevation to a higher elevation. An inclined plane is one of six types of simple machines, and it is one of the oldest and most basic. In fact, two other simple machines, the wedge and the screw, are variations of the inclined plane.

A ramp like the one in the Figure below is another example of an inclined plane. Inclined planes make it easier to move objects to a higher elevation. The sloping surface of the inclined plane supports part of the weight of the object as it moves up the slope. As a result, it takes less force to move the object uphill. The trade-off is that the object must be moved over a greater distance than if it were moved straight up to the higher elevation.

good explanation buddy give that person brainliest

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g