Calculate the energy required to heat of ethanol from to . Assume the specific heat capacity of ethanol under these conditions is . Be sure your answer has the correct number of significant digits.

17 kJ

Explanation:

Calculation for the Calculate the energy required to heat 0.60kg of ethanol from 2.2°C to 13.7°C.

Using this formula

q = mC∆T

Where,

q represent Energy

m represent Mass of substance=0.60kg=600g

C represent Specific heat capacity=2.44J·g−1K−1.

∆T represent change in Temperature=2.2°C to 13.7°C.

Let plug in the formula

q=(0.60 kg x 1000 g/kg)(2.44 J/gº)(13.7°C-2.2°C)

q = (600g)(2.44 J/gº)(11.5º)

q=16.836 kJ

q= 17 kJ (Approximately)

Therefore the energy required to heat 0.60kg of ethanol from 2.2°C to 13.7°C will be 17 kJ

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.

i think it's letter a.