In a chemical reaction, 247 g of copper carbonate was heated and 149.2 g of copper oxide was made.

a. RFM CuCO₃ = 123.5

RFM CuO = 79.5

b. 159 g

c. 93.84%

Given

247 g of copper carbonate

149.2 g of copper oxide

Required

a. RFM(relative formula mass)

b. the mass of CuO

c. % yield

Solution

Reaction

CuCO₃⇒CuO+CO₂

a.

RFM CuCO₃ = 63.5+12+3.16=123.5

RFM CuO = 63.5 + 16 = 79.5

b. mol CuCO₃ :

mol = mass : MW

mol = 247 : 123.5

mol = 2

From equation, mol ratio CuCO₃ : CuO = 1 :1 , so mol CuO = 2

mass CuO = 2 x 79.5 = 159 g

c. % yield = (actual/theoretical) x 100%

%yield = (149.2/159) x 100% = 93.84%

chemical digestion occurs in the stomach were hcl and pepsin forms chyme, the mouth in which salivary amylase breaks down starch to form bolus, and the small intestine specifically the duodenum.