CaC2 + 2H2O(I) = C2H2(g) + Ca(OH)2(aq) how many grams of Ca(OH)2 would be formed with 3.20 moles of CaC2?

The mass of Ca(OH)₂ produced from the reaction is 236.8 g

CaC₂ + 2H₂O —> C₂H₂+ Ca(OH)₂

From the balanced equation above,

1 mole of CaC₂ reacted to produce 1 mole of Ca(OH)₂

Therefore,

3.20 moles of CaC₂ will also react to produce to 3.20 moles of Ca(OH)₂

Mass = mole × molar mass

Mass of Ca(OH)₂ = 3.20 × 74

Mass of Ca(OH)₂ = 236.8 g

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236.8 g

Explanation:

From the reaction equation;

CaC2 + 2H2O(I) > C2H2(g) + Ca(OH)2(aq)

Since;

1 mole of CaC2 yields 1 mole of Ca(OH)2

It follows that 3.20 moles of CaC2 also yields 3.2 moles of Ca(OH)2

Mass of Ca(OH)2 = number of moles * molar mass

molar mass of Ca(OH)2 = 74 g/mol

Mass of Ca(OH)2 = 3.20 moles * 74 g/mol =

Mass of Ca(OH)2 = 236.8 g

i do not get it   at all