If 255 J of heat is applied to 20.0 g of gold, what temperature change will
occur if the specific heat of gold is 0.129 j/g C

ΔT  = 98.84 °C

Explanation:

Given data:

Heat absorbed = 255 J

Mass of gold = 20.0 g

Specific heat capacity of gold = 0.129 J/g.°C

Temperature change = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

by putting values,

255 J = 20.0 g × 0.129 J/g.°C × ΔT

255 J  = 2.58 J / °C × ΔT

ΔT  = 255 J  / 2.58 J / °C

ΔT  = 98.84 °C

your picture is not part of the scientific method.

specific gravity is the density of a substance divided by the density of water. since (at standard temperature and pressure) water has a density of 1 gram/cm3, and since all of the units cancel, specific gravity is usually very close to the same value as density

so "c" is the answer

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