What is the change in temperature if
2355 cal heats 51.5 g of water?

45.73°C

Explanation:

Given parameters:

Quantity of heat  = 2355cal

Mass of water  = 51.5g

Unknown:

Change in temperature  = ?

Solution:

To solve this problem, use the expression below;

      H  = m c Ф  

H is the quantity of heat

m is the mass

c is the specific heat of water  = 1cal/g°C

Ф is the change in temperature  = ?

Now insert the parameters and solve;

          H  = 51.5 x 1 x Ф  

      2355  = 51.5 x Ф

          Ф   = 45.73°C

"among the transition metal elements, manganese and zinc have a slight lowering of electronegativities. the reason behind this is that the nuclear charges of these elements are slightly weaker than the other transition metal elements due to the way their valence electrons are filled up. both manganese and zinc have their valence electrons filled up to the 4th shell with 1 pair of electrons (4s2) completely occupying it. although the electrons in the 3rd shell (3d) are yet to be paired since the outer most shell is filled up, the ability of the nucleus to attract electrons is lessened. hence,   the electronegativity (or the ability to attract electrons) is lessened."

fr8t7iot7o87oglgt87ot79p0[90