Calculate the concentration of a solution containing 1.8g of sodium carbonate in 862cm3 of water

0.02 M

Explanation:

Given data:

Mass of sodium carbonate = 1.8 g

Volume of water = 862 cm³ (862/1000 = 0.862 L)

Concentration = ?

Solution:

Formula:

Concentration  = number of moles / volume in L

Number of moles of sodium carbonate:

Number of moles = mass/molar mass

Number of moles = 1.8 g/ 106 g/mol

Number of moles = 0.02 mol

Concentration:

c = 0.02 mol / 0.862 L

c = 0.02 M

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its first and third is your answer i did the qustion the fourth isnt right