Determine molar concentration of the equivalent of acetic acid in 6% solution (d=1g/ml)

Molar concentration of acetic acid = 1 M

Given

acetic acid in 6% solution (d=1 g/ml)

Required

molar concentration

Solution

mass of acetic acid in solution

mass = density x %mass

mass = 1 g/ml x 6%

mass = 0.06 g/ml ⇒ 60 g/L

MW acetic acid = 60 g/mol

molarity acetic acid = mass : MW

molarity = 60 g/L : 60 g/mol

molarity = 1 mol / L = 1 M