Please help! Magnesium Sulphate can be made from magnesium and dilute sulfuric acid. Mg + H2SO4 -> MgSO4 + H2. calculate the mass of magnesium sulfate that would be obtained from 4G of magnesium.

20 g of MgSO₄.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

Mg + H₂SO₄ —> MgSO₄ + H₂

Next, we shall determine the mass of Mg that reacted and the mass of MgSO₄ produced from the balanced equation. This is illustrated below:

Molar mass of Mg = 24 g/mol

Mass of Mg from the balanced equation = 1 × 24 = 24 g

Molar mass of MgSO₄ = 24 + 32 + (16×4)

= 24 + 32 + 64

= 120 g/mol

Mass of MgSO₄ from the balanced equation = 1 × 120 = 120 g

SUMMARY:

From the balanced equation above,

24 g of Mg reacted to produce 120 g of MgSO₄.

Finally, we shall determine the mass of MgSO₄ produced by the reaction of 4 g of Mg. This can be obtained as follow:

From the balanced equation above,

24 g of Mg reacted to produce 120 g of MgSO₄.

Therefore, 4 g of Mg will react to produce = (4 × 120)/24 = 20 g of MgSO₄.

Thus, 20 g of MgSO₄ is obtained from the reaction.