A coiled spring with coils that are closely spaced then widely then closely then widely then closely, ending with a yellow line labeled 1 second. What is the frequency of this wave?

The frequency of the wave is 2Hz.

Explanation:

The frequency of a wave is the number of waves that pass a fixed point in a given amount of time. It can be measured by counting the number of crests that pass the point in a given time period. The higher the number is, the greater is the frequency of the wave.

So, by counting the number of times the coils in the spring are widely spaced, which is 2 times in 1 second, we get the frequency of the wave.

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer