Queston Which equation shows how to calculate how many grams (g) of KOH would
be needed to fully react with 4 mol Mg(OH)2? The balanced reaction is:
MgCl2 + 2KOH → Mg(OH)2 + 2KCI
OA. mol Mg(OH),
2 mol KOH
mol Mg(0H),
56.10 g KOH
1 mol KOH
2 mol KOH
1 mol Mg Cl,
56.10 g KOH
1mol KOH
OB. mol Mgch
1
1mol Mg(OH),
2 mol KOH
1mol Ma(0H),
56.10 g KOH
1 molkOH
mol Mg (OH,
1 mol KOH
2 mol Ma(OH)
56 10 g KOH
1mol KOH
OD.

Nitric acid can be formed in two steps from the atmospheric gases nitrogen and oxygen, plus hydrogen prepared by reforming natural gas. in the first step, nitrogen and hydrogen react to form ammonia: (g) (g) (g) in the second step, ammonia and oxygen react to form nitric acid and water: (g) (g) (g) (g) calculate the net change in enthalpy for the formation of one mole of nitric acid from nitrogen, hydrogen and oxygen from these reactions. round your answer to the nearest .