Chemistry
Chemistry, 08.01.2021 07:50, zwalkert01

Consider the chemical equations shown here. 2H2(g) + O2(g) β†’ 2H2O(g) AH, = -483.6 kJ = 2 =-241.8 kJ/mol
302(9) β–Ί 203(9) AH2 = 284.6 kJ = 2 = 142.3 kJ/mol
What is the overall enthalpy of reaction for the equation shown below?
3H2(g) + O2(g) β†’ 3H20 (g)
kJ

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Consider the chemical equations shown here. 2H2(g) + O2(g) β†’ 2H2O(g) AH, = -483.6 kJ = 2 =-241.8 kJ...

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