Chemistry, 07.01.2021 20:30, grumpygirl0720

Iron forms both 2+ and 3+ cations. Write formulas for the oxide, sulfide, and chloride compounds of the 3+ iron cation.

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answered: ptrlvn01

Fe2O3, Fe2S3 and FeCl3

Explanation:

The formular shows the number of atoms of element present in the compound. The number of atoms in turn depends on the charges. The goal is to have a neutral compound with oxidation number of zero.

Oxide:

Iron(Fe) has oxidation number (O.N) of +3, oxygen has O.N of -2. The formular with a balanced (Charge = 0) O.N number is; Fe2O3

Sulphide:

Iron(Fe) has oxidation number (O.N) of +3, sulphur has O.N of -2. The formular with a balanced (Charge = 0) O.N number is; Fe2S3

Chloride:

Iron(Fe) has oxidation number (O.N) of +3, chlorine has O.N of -1. The formular with a balanced (Charge = 0) O.N number is; FeCl3

answered: Guest

the number of protons in the nucleus of a given element. has slight luster and conducts electricity at high temperatures like metal.but like a nonmetal,boron is brittle and does not conduct electricity well at low temperatures. in graphite, carbon is a soft,brittle solid.it is reflective,ductile,or malleable.

answered: Guest

remember that hf is only the energy of one photon. not two. not three. one. 1) 5.12 * 10^3 photons find the energy of one photon, then determine how many photons are needed to reach the sensitivity. e = hf = (6.626 * 10^-34 js)(5.95 * 10^19 hz) = 3.94247 * 10^-14 j per photon (2.02 * 10^-10 j) / (3.94247 * 10^-14 j/photon) = 5123.69149 photons round to three sig figs. 2) 5.77 * 10^-17 j energy of pulse = energy per photon * number of photons = hfn = (6.626 * 10^-34 js)(1.66 * 10^13 hz)(5250) = 5.774559 * 10^-17 j round to three sig figs. 3) 4.07 * 10^8 kj/mol 10^12 pm = 1 m c = fλ f = c/λ e = hf = hc/λ = [(6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.94 * 10^-12 m)](1 kj/1000 j)(6.02 * 10^23 photons/mol) = 40702571.4 kj/mol round to three sig figs. 4) 9.94 * 10^-1 m e = hc/λ λ = hc / e = (6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.00 * 10^-25 j) = 0.9939 m round to three sig figs. 5) 9.06 * 10^3 photons energy of pulse = energy per photon * number of photons number of photons = energy of pulse / energy per photon = energy of pulse / (hf) = (3.87 * 10^-13 j) / [(6.626 * 10^-34 js)(6.45 * 10^16 hz)] = 9055.23695 photons round to three sig figs. 6) 2.78 * 10^-15 j this is problem 1, except in reverse. sensitivity = minumum number of photons * energy per photon = (5930)(6.626 * 10^-34 js)(7.077 * 10^14 hz) = 2.78070758 × 10^-15 j round to three sig figs.

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Iron forms both 2+ and 3+ cations. Write formulas for the oxide, sulfide, and chloride compounds of...