How much heat, in joules, is required to warm a metal disc from 19 °C to 33 °C? The mass of the disc is 3.0 grams and the specific heat of the disc is 2.3 J/gºC.
Nuestion 5

Q = 96.6 j

Explanation:

Given data:

Heat required = ?

Initial temperature = 19°C

Final temperature = 33°C

Mass of disc = 3.0 g

Specific heat capacity = 2.3 J/g.°C

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 33°C - 19°C

ΔT = 14°C

Q = 3.0 g×2.3 J/g.°C × 14°C

Q = 96.6 j

a graduated cylinder.

explanation:

43.452

step-by-step explanation:

284 times .153 = 43.452