What mass of nitrogen occupies a volume of 11.2 L, if 4.20 g of nitrogen occupies 100. L?

0.47 g

Explanation:

From the question given above, we obtained the following information:

4.20 g of nitrogen occupies 100 L.

We can obtain the mass of nitrogen that occupied 11.2 L by doing the following:

4.20 g of nitrogen occupies 100 L.

Therefore, Xg of nitrogen will occupy 11.2 L i.e

Xg of nitrogen = (11.2 × 4.2) / 100

Xg of nitrogen = 0.47 g

From the calculation made above, 0.47 g of nitrogen will occupy 11.2 L