Place the following in order of increasing X-Se-X bond angle, where X represents the outer atoms 7) in each molecule. SeO2 SeCl6 SeF2 A) SeF2 SeO2< SeCl6
B) Seo2 C) SeF2 < SeCl6 SeO2
D) SeCl6 < SeF2 Se02

SeCl₆ < SeF₂ <  SeO₂

Explanation:

To determine the order of the bond angle of the compound, we need to determine the hybridization of each compound given.

For:

SeO₂, The hybridization is sp² because the Se is doubly bonded to O at both sides and Se contains a lone pair of electrons.

SeCl₆, Se is attached to six different Cl atoms via a single bond in a hexagonal shape. Thus, SeCl₆ hybridization is sp³d²

SeF₂, Here, Se is singly bonded to F atoms on both sides and Se contains a lone pair of electrons. The hybridization is sp³

Therefore, the bond angle in sp² = 120°, sp³ = 109.8°, sp³d² = 90°

Hence, the order is:  SeCl₆ < SeF₂ <  SeO₂

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.