Molecular iodine, I2(g)
dissociates into iodine atoms at 625 K with a first-order rate constant of
0.271s-1
What is the half-life for this reaction?

Half-life for this reaction is 2.56s

Explanation:

The general expression in a reaction that follows first-order is:

Ln[A] = -kt + ln[A]₀

Where [A] is concentration of reactant after time t,

k is rate constant = 0.271s⁻¹

[A]₀ is initial concentration of reactant.

Half-life is defined as the time required to decrease the initial concentration of the reactant (I2 in this case) halved.

If [A]₀ = 1

[A] = 1/2

Solving the equation:

Ln[1/2] = -0.271s⁻¹*t + ln[1]

Ln[1/2] = -0.271s⁻¹*t + 0

Ln[1/2] = -0.271s⁻¹t

Ln 2 = 0.271s⁻¹

2.56s = t

Half-life for this reaction is 2.56s

answer: e.   sour taste

explanation: acids are those substances which dissociates in water to give ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. acids are sour in taste. example: hcl

bases are those substances which dissociates in water to give ions or accepts ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. bases are bitter in taste. bases are slippery in nature.