What is the mass of a solution containing 0.2 molar of sodium chloride

Explanation:

The reaction is FeCl

3+3NaOH→Fe(OH) 3+3NaCl.

Thus, 1 mole of ferric chloride will react with 3 moles of NaOH to form one mole of ferric hydroxide.

0.24 moles of sodium hydroxide will react with 0.08 moles of ferric chloride to form 0.08 moles of ferric hydroxide.

The unreacted amount of ferric chloride is 0.2−0.08=0.12 moles.

In this reaction, sodium hydroxide is the limiting reagent.

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