What is the mass of 3.20x10^23 formula units of iron (III) oxide (Fe2O3)?

We have 84.84g of  FeO in 3.20*10^23 particles.

Data;

To solve this problem, we need to relate Avogadro number to the molar mass.

From molar mass - Avogadro's number relationship;

From the above calculations, 84.84g of FeO is present in 3.20*10^23 particles of  FeO.

Learn more on Avogadro's number here;

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The mass of iron (III) oxide (Fe2O3) : 85.12 g

Given

3.20x10²³ formula units

Required

The mass

Solution

1 mole = 6.02.10²³ particles  

Can be formulated :

N = n x No

N = number of particles

n = mol

No = 6.02.10²³ = Avogadro's number

mol of Fe₂O₃ :

mass of Fe₂O₃ (MW=160 g/mol)

answer: option (b) is the correct answer.

explanation:

a covalent bond is formed by sharing of electrons. whereas polarity arises due to difference in electronegativity of two atoms.

therefore, more is the electronegativity of an atom which combines with the titanium, more readily it will induce a partial positive and negative charge.

thus, out of the given options fluorine is most electronegative and has an incomplete octet. therefore, it will readily combine with titanium to share the electrons and complete its octet.  

personal, she chose to do it.