25cm3 of a 0.4M sodium hydroxide solution was diluted into 250cm3 of water. What is the molarityof the resultant solution.

0.04 M

Explanation:

From the question given above, the following data were obtained:

Initial volume of solution (V1) = 25 cm³

Initial Molarity of solution (M1) = 0.4 M

Final volume of solution (V2) = 250 cm³

Final Molarity of solution (M2) =?

We can obtain the final Molarity of the solution by using the dilution formula as illustrated below:

M1V1 = M2V2

0.4 × 25 = M2 × 250

10 = M2 × 250

Divide both side by 250

M2 = 10/250

M2 = 0.04 M

Therefore, the resulting molarity of the diluted solution is 0.04 M

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :