Now, let's solve our problem using Boyle's Law: A gas that exerts a pressure of 151 mm Hg in a
container with a volume of
L will exert a
pressure of 166 mm Hg when transferred to a
container with a volume of 0.532 L.
[?]L
Assume that the number of moles and the
temperature remain constant.

V₁ = 0.585 L

Explanation:

Given data:

Initial pressure = 151 mmHg

Initial volume = ?

Final pressure = 166 mmHg

Final volume = 0.532 L

Solution:

The given problem will be solved through the Boyle's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

151 mmHg × V₁ = 166 mmHg × 0.532 L

V₁ = 166 mmHg × 0.532 L / 151 mmHg

V₁ = 88.312mmHg .L /151 mmHg

V₁ = 0.585 L

is has three carbons, so the answer is propylamine.

meth-

eth-

prop-

but-

pent-

hex-

hept-

oct-

non-

explanation: