Chemistry, 27.12.2020 20:40, reganjones89
In an experiment, 0.4 mol of sulphur trioxide gas, SO3 (g) was allowed to dissociate to sulphur
dioxide gas, SO2 (g) and oxygen gas, O2 (g) in a 1.00 Litre container and allow to reach equilibrium
at constant temperature. The equation of the reaction is given as follow:
SO3 (g) =SO2 (g) + 1/2O2 (g)
The number of mole of SO3 at equilibrium is 0.32 mol, SO2 is 0.08 mol and O2 is 0.16 mol Sketch
the graph of concentration against the time for this reaction.
Answers: 2
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In an experiment, 0.4 mol of sulphur trioxide gas, SO3 (g) was allowed to dissociate to sulphur
dio...
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