What is the standard reduction potential, E, for the half-reaction Zn2+(aq)+2e- -> Zn(s)?

E = -0.76 V

Explanation:

The potential between the anode and the cathode is called standard reduction potential. It gives the tendency of the species to get reduced.

The given half reaction is :

Zn²⁺ is the reduced form of Zn.

It is a stronger reducng agent.

Its standard reduction potential (E) has a sandard value.

E = -0.76 V

Hence, the correct option is (c).

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

i don,t know so just answer mine