You have been given the task to analyze a large number of samples that contain an unknown concentration of the diprotic acid, oxalic acid. You know the concentration is approximately 0.005 to 0.015 M H2C2O4 . However, you do not want to complete a myriad of pH titrations, so you decide to identify some of the expected pH values you will encounter. In order to do so, you have prepared 50.00 mL of 0.0110 M H2C2O4 solution as your test solution. You will be titrating the H2C2O4 solutions with 0.0160 M NaOH. Based on this information: (1) Calculate the pH of the titration solution once the first equivalence point has been reached. (2) Calculate the pH of the titration solution once the second equivalence point has been reached. (3) Calculate the pH of the titration solution once 150.0 mL of the NaOH has been added.

answer is: empirical formula is tl₂o. if we use 100 grams of compound, tha:

m(tl) = 96.2%  · 100 g ÷ 100%.

m(tl) = 96.2 g.

n(tl) = m(tl)  ÷ m(tl). n(tl) = 96.2 g  ÷ 204.4 g/mol.

n(tl) = 0.47 mol. m(o) = 3.77 g. n(o) = m(o)  ÷ m(o). n(o) = 3.77 g  ÷ 16 g/mol. n(ag) = 0.235 mol. n(tl) . n(o) = 0.47 mol : 0.235 mol /0.235. n(tl) . n(o) = 2 : 1.

m(tl₂o) = 204.4 g/mol  · 2 + 16 g/mol = 424.8 g/mol.

m(compound) = 456. 8 g/mol - 424.8 g/mol = 32 g/mol ( 2 oxygens); tl₂o₃. 

brian made this table to organize his notes on changes of state. depostion is a change of state that has the wrong energy change listed. it is utilized to collect data as a portion of the development means and in restricted conditions which may be applied at test.

a deposition in the authority of the united states or research for development in the authority of canada includes the catching of affirmed. the out-of-court verbal assertion of a spectator that may be lessened to a printed record for succeeding application for discovery purposes.