if you start with 55 grams of sodium flouride naf how many grams of magnesium fluride mgf2 will be produced

Mass of MgF₂ formed = 40.5 g

Explanation:

Given data:

Mass of NaF = 55 g

Mass of MgF₂ formed =  ?

Solution:

Chemical equation:

2NaF  +  Mg      →     MgF₂ + 2Na

Number of moles of NaF:

Number of moles = mass/molar mass

Number of moles = 55 g / 41.98 g/mol

Number of moles = 1.3 mol

now we will compare the moles of sodium fluoride with magnesium fluoride.

                     NaF       :          MgF₂

                       2          :             1

                     1.3          :        1/2×1.3 =  0.65 mol

Mass of magnesium fluoride:

Mass = number of moles × molar mass

Mass = 0.65 mol × 62.3 g/mol

Mass = 40.5 g

since the atomic number is the number of protons in the nucleus, as we move to the left on the periodic table, the electrostatic pull between the nucleus and the valence electron shell decreases. as we move down a group (vertical column), the valence shell energy level gets further and further from the nucleus.