A motorist discovers that her auto tire measures 29.2 psi rather than the recommended 35 psi. If the tire’s volume is assumed constant at 11.6 L and the temperature is 45F at the filling station, how many moles of air will the motorist need to add to bring the tire to 35 psi? (assume 1.00 atm = 14.7 psi)

  0.20 moles

Explanation:

The pressure is proportional to the quantity of gas at a given temperature and volume. So, the quantity needs to be increased by a factor of ...

  (35 psi)/(29.2 psi) = 175/146 ≈ 1.19863

The fractional increase required is ...

  1.19863 -1 = 0.19863

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The quantity of air currently in the tire is ...

  1 mol·519.67°R/(atm·23.6442 L) × (29.2/14.7 atm) × (11.6 L) / (45+459.67)°R

  = 1.0035 mol

so we need to add ...

  (fraction to add) × (current quantity) = amount to add

  0.19863 × 1.0035 mol = 0.1993 mol = amount to add

About 0.20 moles of air must be added to the tire to bring the pressure up.

i'm assuming that it's c.) red bank..

the answer to your question is c