If 0.031 mg of Pb2+ was observed in 1.29 kg of solution what is the ppm?

Volume of solution = 577.83 ml (Approx)

Explanation:

Given:

% of (W/V) = 8.48%

Weight of KBr in gram = 49 gram

Find:

Volume of solution

Computation:

% of (W/V) = Weight of KBr in gram / Volume of solution

8.48% = 48 / Volume of solution

Volume of solution = 49 / 8.48%

Volume of solution = 577.83 ml (Approx)

alfred von schlieffen, german army chief of staff, was given instructions to devise a strategy that would be able to counter a joint attack. in december, 1905, he began circulating what later became known as the schlieffen plan. schlieffen argued that if war took place it was vital that france was speedily defeated.

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.