Compared to the ideal bond angle, the actual/real bond angle in a molecule of water will be:. a. the same.
b. larger.
c. depends on the number of oxygen atoms.
d. smaller.

d. smaller.

Explanation:

Hybridization :

N = number of electrons

where, V = number of valence electrons present in central atom i.e. oxygen = 6

N = number of monovalent atoms bonded to central atom=32

C = charge of cation = 0

A = charge of anion = 0

The number of electrons is 4 that means the hybridization will be and the electronic geometry of the molecule will be tetrahedral.  The bond angle for tetrahedral geometry is

But as there are two atoms around the central oxygen, the third and fourth position will be occupied by lone pair of electrons. The repulsion between lone and bond pair of electrons is more and hence the molecular geometry will be bent and the bond angle will be smaller than expected and is

i believe the answer is 5,000

the seeing the electronic configuration we can say that the element is fluorine.

fluorine is the most electronegative element in the periodic table.

but by only seeing the configuration we cannot say about its reactivity because we don't know if its configuration after excitation or by addition of electrons.

but if not then, it is the lightest halogen and exists as a highly toxic pale yellow diatomic gas at standard conditions. as the most electronegative element, it is extremely reactive: almost all other elements, including some noble gases, form compounds with fluorine.