Chemistry, 17.12.2020 02:40, isabelgarcia188

1. 2g of calcium carbonate was added to 40 cm3 of hydrochloric acid of concentration 2 moldm-3. Write a balanced equation for the reaction. (2 mrks)

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answered: RG1971

The balanced equation :

CaCO₃ (s) + 2HCl (aq) → CaCl₂ (aq) + H₂O (l) + CO₂ (g)

Further explanation

Equalization of chemical reaction equations can be done using variables. Steps in equalizing the reaction equation:

1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c etc.

2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index between reactant and product

3. Select the coefficient of the substance with the most complex chemical formula equal to 1

CaCO₃ (s) + HCl (aq) → CaCl₂ (aq) + H₂O (l) + CO₂ (g)

Give coefficient :

CaCO₃ (s) + aHCl (aq) → bCaCl₂ (aq) + cH₂O (l) + dCO₂ (g)

Ca, left=1, right=b⇒b=1

C, left=1, right=d⇒d=1

O, left=3, right=c+2d⇒3=c+2d⇒3=c+2.1⇒c=1

H, left=a, right=2c⇒a=2c⇒a=2.1⇒a=2

the equation becomes :

CaCO₃ (s) + 2HCl (aq) → CaCl₂ (aq) + H₂O (l) + CO₂ (g)

answered: Guest

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in $h_{2}s$ , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between $h_{2}s$ molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent $h_{2}s$ molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.