What is the answer to part c and how do we do it?

The answer to part c is the amount of moles of FeBr₃ that will be formed is approximately 0.179 moles

Explanation:

The given chemical reaction is 2Fe + Br₂ → 2FeBr₃

The mass of iron, Fe, in the reaction = 10 g

a) The amount of moles of iron that reacted = The mass of iron in the reaction/(The molar mass of iron)

The atomic mass of iron = 56 amu

Therefore, one mole of iron = 56 grams

The amount of moles of iron that reacted = 10/(56) ≈ 0.179

The amount of moles of iron that reacted ≈ 0.179 moles

b) The amount of moles of bromine that reacted = 3/2 × The amount of moles of iron that reacted

∴ The amount of moles of bromine that reacted = 3/2 × 0.179 ≈ 0.2685

The amount of moles of bromine that reacted ≈ 0.2685 moles

c) The amount of moles of FeBr₃ that will be formed = The amount of moles of iron in the reaction ≈ 0.179 moles

d) The mass of one molecule of FeBr₃ = Mass of 1 atom of iron, Fe + 3 × The mass of 1 atom of bromine, Br

∴ The mass of one mole of FeBr₃ =  56 + 3 × 80 = 296

The mass of one mole of FeBr₃ = The molar mass of FeBr₃ =  296 grams

The mass of FeBr₃ formed = The molar mass of FeBr₃ × The number of moles of FeBr₃ formed

∴ The mass of FeBr₃ formed = 296 × 0.179 ≈ 52.984

The mass of FeBr₃ formed  ≈ 52.984 grams

dynamic equilibrium is the answer.