How many grams of oxygen, O2 are produced if 52.0g of potassium chlorate, KClO3, decomposes? (The molar mass of O2 = 32 g/mol and the molar mass of KClO3 = 122.4 g/mol).

20.39 g of O2.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2KClO3 —> 2KCl + 3O2

Next, we shall determine the mass of KClO3 that decomposed and the mass of O2 produced from the balanced equation. This is illustrated below:

Molar mass of KClO3 = 122.4 g/mol

Mass of KClO3 from the balanced equation = 2 × 122.4 = 244.8 g

Molar mass of O2 = 32 g/mol

Mass of O2 from the balanced equation = 3 × 32 = 96 g

Summary:

From the balanced equation above,

244.8 g of KClO3 decomposed to produce 96 g of O2.

Finally, we shall determine the mass of O2 produced from the decomposition of 52 g of KClO3. This can be obtained as follow:

From the balanced equation above,

244.8 g of KClO3 decomposed to produce 96 g of O2.

Therefore, 52 g of KClO3 will decompose to produce =

(52 × 96)/244.8 = 20.39 g of O2.

Thus, 20.39 g of O2 is produced.