A 700 mL sample of gas at STP is compressed to 300 mL, and the temperature is raised to 100.C. What is the new pressure of the gas in atm?

P₂ =  3.19 atm

Explanation:

Given data:

Initial volume = 700 mL

Initial pressure = 1 atm

Initial temperature = 273K

Final temperature =100°C (100+273= 373 K)

Final volume = 300 mL

Final pressure = ?

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

P₂ = P₁V₁ T₂/ T₁ V₂  

P₂ = 1 atm × 700 mL × 373K / 273 K ×300 mL  

P₂ = 261100 atm .mL. K   /81900 K .mL

P₂ =  3.19 atm

the answer to your question is c.

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