Consider the following chemical reaction. CaF2(s) + H2SO4(aq) → CaSO4(s) + 2 HF(g)
When a certain amount of calcium fluoride (CaF2) reacts with sulfuric acid (H2SO4) in excess, the theoretical yield of hydrogen fluoride (HF) is 3.08 g. If the percent yield is 83.9%, what is the actual yield of HF in grams?

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explanation:

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.