What is the molarity of a solution prepared by dissolving 1.25g of HCl gas into enough water to make 30cm3 of solution

The molarity of a solution : 1.13 M

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

mass HCl = 1.25 g

mol HCl(MW=36.5 g/mol) :

Volume of solution = 30 cm³ = 0.03 L

The molarity :

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm