Is my answer correct?
Can someone explain how to get the right net ionic equation

Option D.

2Ag⁺(aq) + Ni(s) —> 2Ag(s) + Ni²⁺(aq)

Explanation:

From the question given above:

Ni(s) —> Ni²⁺(aq) + 2e¯

Ag⁺(aq) + e¯ —> Ag(s)

We can obtain the net ionic equation by combining both equation as shown below:

Ag⁺(aq) + e¯ + Ni(s) —> Ag(s) + Ni²⁺(aq) + 2e¯

Next, we shall balance the equation. This can be obtained as follow:

Ag⁺(aq) + e¯ + Ni(s) —> Ag(s) + Ni²⁺(aq) + 2e¯

There are 2 atoms of e¯ on the right side and 1 atom on the left side. It can be balance by putting 2 in front of e¯ as shown below:

Ag⁺(aq) + 2e¯ + Ni(s) —> Ag(s) + Ni²⁺(aq) + 2e¯

Next, we shall balance the charge on both sides. This is illustrated below:

TOTAL charge on the left = +1 + (–2)

= 1 – 2

= –1

TOTAL charge on the right side = +2 + (–2)

= 2 – 2

= 0

Thus, to balance the charge, put 2 in front of Ag⁺ as shown below:

2Ag⁺(aq) + 2e¯ + Ni(s) —> Ag(s) + Ni²⁺(aq) + 2e¯

There are 2 atoms of Ag on the left side and 1 atom on the right side. It can be balance by putting 2 in front of Ag as shown below:

2Ag⁺(aq) + 2e¯ + Ni(s) —> 2Ag(s) + Ni²⁺(aq) + 2e¯

Next, cancel out 2e¯ from both side to obtain the net ionic equation. Thus, we have:

2Ag⁺(aq) + Ni(s) —> 2Ag(s) + Ni²⁺(aq)

because u need two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei to form isotopes.

so since they all have the same shape? i mean maybe because m& m and reeses are both chocolates