Is my answer correct?
Can someone explain how to get the right net ionic equation

Option D.

2Ag⁺(aq) + Ni(s) —> 2Ag(s) + Ni²⁺(aq)

Explanation:

From the question given above:

Ni(s) —> Ni²⁺(aq) + 2e¯

Ag⁺(aq) + e¯ —> Ag(s)

We can obtain the net ionic equation by combining both equation as shown below:

Ag⁺(aq) + e¯ + Ni(s) —> Ag(s) + Ni²⁺(aq) + 2e¯

Next, we shall balance the equation. This can be obtained as follow:

Ag⁺(aq) + e¯ + Ni(s) —> Ag(s) + Ni²⁺(aq) + 2e¯

There are 2 atoms of e¯ on the right side and 1 atom on the left side. It can be balance by putting 2 in front of e¯ as shown below:

Ag⁺(aq) + 2e¯ + Ni(s) —> Ag(s) + Ni²⁺(aq) + 2e¯

Next, we shall balance the charge on both sides. This is illustrated below:

TOTAL charge on the left = +1 + (–2)

= 1 – 2

= –1

TOTAL charge on the right side = +2 + (–2)

= 2 – 2

= 0

Thus, to balance the charge, put 2 in front of Ag⁺ as shown below:

2Ag⁺(aq) + 2e¯ + Ni(s) —> Ag(s) + Ni²⁺(aq) + 2e¯

There are 2 atoms of Ag on the left side and 1 atom on the right side. It can be balance by putting 2 in front of Ag as shown below:

2Ag⁺(aq) + 2e¯ + Ni(s) —> 2Ag(s) + Ni²⁺(aq) + 2e¯

Next, cancel out 2e¯ from both side to obtain the net ionic equation. Thus, we have:

2Ag⁺(aq) + Ni(s) —> 2Ag(s) + Ni²⁺(aq)